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Showing results for tags 'sequence'.
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How do I compose a job that only contains every 250-th record? I used the Sequential Numbering rule with the start number (76751) and there is no datafile involved. So for the total of 10.000 records I need only 40 records with 249 records skipped each time. On the same page is also a number printed from 1 to 40; but that is already working with a javascript-rule. Thanks for your help! Greetings from the Netherlands
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Background: Simple coupons with sequential numbering set 4Up on a sheet. Problem: Sequential starting number works if I don't have "stack" set in the imposer. Once "stack" is set the starting number is disregarded and begins at 1. OnJobStart Code: var startNumber = 69000; //Enter the begin number provided. var totalCoupons = 1875; //Enter the number of total coupons var endNumber = (startNumber + totalCoupons) - 1; FusionPro.Composition.composeAllRecords = false; FusionPro.Composition.startRecordNumber = startNumber; FusionPro.Composition.endRecordNumber = endNumber; Empty Rule Code (CouponNumber): return CurrentRecordNumber(); FusionPro Imposer Settings: Simplex Stack Count 10000 OR Checked Infinite Stack Vertical Count 4 0" Spacing Goal: To have a coupon numbering system that did the counting down stack starting at a number other than 1 Answer: Made suggested changes to OnJobStart code and EmptyRule code provided by tou in the second post. Thanks! ^^,