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Old August 8th, 2018, 11:18 AM
sandig199 sandig199 is offline
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Join Date: Jul 2018
Location: Grand Rapids MI EST
Posts: 13
Default Array stop and start

I have an array of values, but I need to be able to "stop" the array when a value is "nothing" and then continue to start a new array with the next series of values.


Example: [value1,value2,value3,value4,value5,value6,value7,v alue8,value9]
if value1,value2 have a value then Array1 = [value1,value2]


if value3 == "", then the array stops.


And start a new array picking up where we left off
Array2 = [value4]


if value5 == "", then the array stops.


and pick up where we left off
Array3 = [value6,value7,value8,value9]


Is this possible?
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  #2  
Old August 8th, 2018, 12:48 PM
Dan Korn's Avatar
Dan Korn Dan Korn is offline
FusionPro Senior Engineer / Forum Moderator
 
Join Date: Aug 2008
Location: Chicago, IL
Posts: 4,478
Default Re: Array stop and start

Sure, something like this:
Code:
var arr = [1,2,3,,5,6,,8,9];

var result = [[]];
for (var i in arr)
{
    var el = arr[i];
    if (el)
        result[result.length-1].push(el);
    else
        result.push([]);
}
return result.join('\n');
Where the result is an array of arrays.

By the way, this kind of purely generic JavaScript question (with nothing specific to FusionPro) can be asked almost anywhere on the web, such as Stack Overflow:
https://stackoverflow.com/questions/tagged/javascript

Or just type your question into Google. (Though in this particular case, my Google-fu wasn't good enough to get a result.)
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